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Math Help - Elimination Method

  1. #1
    Junior Member fluffy_penguin's Avatar
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    Elimination Method

    I keep getting high fractions, I'm no good with fractions.

    http://img295.imageshack.us/img295/1999/p2el3.jpg

    I get: x= 43/73

    Then plugging 43.73 in for x I get

    43/73 + 9y= 21

    Multiply everything by 73

    43+ 657 y = 1533

    657 y = 1490

    y =

    I don't know, just seems like such an odd number to be in a book..
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by fluffy_penguin View Post
    I keep getting high fractions, I'm no good with fractions.

    http://img295.imageshack.us/img295/1999/p2el3.jpg

    I get: x= 43/73

    Then plugging 43.73 in for x I get

    43/73 + 9y= 21

    Multiply everything by 73

    43+ 657 y = 1533

    657 y = 1490

    y =

    I don't know, just seems like such an odd number to be in a book..
    umm. no, there are integer solutions to x and y. show us how you got the x so that we can see where you made your mistake
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  3. #3
    Junior Member fluffy_penguin's Avatar
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    8x-y = 22
    x + 9y=21

    (9) 8x - 9y= 22

    72x - 9y =

    Oh I see it, I didn't multiply the 22 by 9 before I eliminated the y's. I got x =3 now.
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by fluffy_penguin View Post
    8x-y = 22
    x + 9y=21

    (9) 8x - 9y= 22

    72x - 9y =

    Oh I see it, I didn't multiply the 22 by 9 before I eliminated the y's. I got x =3 now.
    yes, and y is?
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  5. #5
    Junior Member fluffy_penguin's Avatar
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    Y = 2

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  6. #6
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by fluffy_penguin View Post
    Y = 2

    correct, good job
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