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Math Help - Solving linear equation, example of my problem

  1. #1
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    Solving linear equation, example of my problem

    I understand how to solve problems with denominators that are variable only for example:


    (1 + x)/ (2x)
    but how does one solve a problem that has a constant integer in the denominator? For example :
    -1/(x+1) = 1 / (3x + 3) - 2 /(x-4)

    I dont know how to find the LCM for an equation like this to multiply on both sides.
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  2. #2
    Super Member Quacky's Avatar
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    Re: Solving linear equation, example of my problem

    Notice that we have:

    \frac{-1}{x+1}=\frac{1}{3(x+1)}-\frac{2}{x-4}

    3(x+1)(x-4) looks like a perfectly reasonable common denominator to me.
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  3. #3
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    Re: Solving linear equation, example of my problem

    Wow. I didn't see that you could simplify 3x + 3 down to 3(x + 1) this makes it much simpler since then you can cancel out x+1 on the other side. Great. Thanks, a ton of help.
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  4. #4
    Super Member Quacky's Avatar
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    Re: Solving linear equation, example of my problem

    If by cancelling you mean multiplying both sides of the equation by it, then I agree. You can't just take them out of both sides as a common factor though.
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