|x-3| >(greater than or equal to) |x| - |3| how do i go about to solve this??? PS why bitdefender anti virus only picking up malware on this forums???
Follow Math Help Forum on Facebook and Google+
Originally Posted by kingmaths $\displaystyle |x-3|\ge |x| - |3|$ Here is a hint: $\displaystyle |x|=|x-3+3|\le |x-3|+|3|$ How can that be rearranged to look this problem?
ok,, but one thing i want to know, do I need to get rid of || sign, if yes how??
Originally Posted by kingmaths ok,, but one thing i want to know, do I need to get rid of || sign, if yes how?? Is not it true for any x?
Originally Posted by kingmaths |x-3| >(greater than or equal to) |x| - |3| how do i go about to solve this??? PS why bitdefender anti virus only picking up malware on this forums??? Looks like a straightforward application of the reverse triangle inequality to me...
View Tag Cloud