px + 4y = 8
6x + 2y =q
p and q are real munbers
Do i slove this equation like a regular simultaneous equations???
We know that:
$\displaystyle x=\frac{8-4y}{p}$
If we substitute this into the other equation we obtain:
$\displaystyle 6\left(\frac{8-4y}{p}\right)+2y=q$
$\displaystyle \Leftrightarrow \frac{48-24y+2py}{p}=q$
$\displaystyle \Leftrightarrow 48+y(-24+2p)=pq$
$\displaystyle \Leftrightarrow y=\frac{pq-48}{2p-24}$