I came upon this question to do with Logs and Fractions which I'm not too sure about.$\displaystyle {3log_{4} x} + \frac{\1}{2} = {5log_{8} x}$

I changed the bases to end up with $\displaystyle \frac{\3lnx}{ln4} - \frac{\5lnx}{ln8} = \frac{\1}{2}$

But forgot the rules about dividing logarithmic functions. Could somebody point me in the right direction please?

P.S. The question asks you to solve for x