find the sum of 4a^3-7a-5 and -8a^2-2a+7 IS THE ANSWER ANSWER: -4n^2-9a+2 HOW TO do this The sum of four consecutive integers is at least 114. Find the smallest possible values for these numbers.
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Originally Posted by Satnam find the sum of 4a^3-7a-5 and -8a^2-2a+7 IS THE ANSWER ANSWER: -4n^2-9a+2 HOW TO do this The sum of four consecutive integers is at least 114. Find the smallest possible values for these numbers. n ??? you may only combine like terms ... $\displaystyle (4a^3 - 7a - 5) + (-8a^2 - 2a + 7) = 4a^3 - 8a^2 - 9a + 2$ integer problem ... $\displaystyle n + (n+1) + (n+2) + (n+3) \ge 114$ solve for n
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