# Math Help - Help with graphics.

1. ## Help with graphics.

Hello!
Today my maths teacher gave me a task. I don't know why he thought that I am some sort of computer GURU but I couldn't deny this task because it is very important for me to automatically get to 10th grade in my school without entrance examination.

The task is to program a graph which automatically solves functions.

Basically it has to work for this function system:
• x(square root) + y(square root) = R(square root)

• x(square root) - y(square root)=number(square root)

I didn't quit understand the whole thing. Teacher said that there isn't a graph for x(square root) - y(square root)=number(square root) and he proved it so I don't know if I have to include it.

Any help will be much apprieciated. Maybe there's already an app or program that can solve this or maybe a website. Anything really will help.

2. ## Re: URGENT! Need help with graphics

I doubt your teacher said that there was no graph. He/she may well have said that this is not a "function". That is, that there can be two different y values for one x value. As for graphing it, the simplest thing to do is to calculate values and mark those points. For example, if x= 0, then $\sqrt{y}= \sqrt{R}$ so that $y= \pm R$. Mark the two points (0, R) and (0, -R). If x= R/4, then $\sqrt{R}{4}+ \sqrt{y}= \sqrt{R}{2}+ \sqrt{y}=\sqrt{R}$ so $\sqrt{y}= \sqrt{R}{2}$ so $y= \pm 4$ also. another two points on the graph are (R/4, R/4) and (R/4, -R/4). If x= R, the equation becomes $\sqrt{R}+ \sqrt{y}= \sqrt{R}$ which leads to $\sqrt{y}= 0$ and y= 0. The point (R, 0) is on the graph.