But what to do about the -3. Eg Do I say:
or
It seems that that it has to be x + 1 < -3 - works if look at curve graphically.
But then what if problem is
and which is wrong. Should be
and .
-4 < x < 2 - can see graphically that is under x axis and so between -4 and 2.
So what is the rule for bit when get square root of either side???
Hello, angypangy!
. . . . Not quite
When we take the square root, we get: .
This means: .
The solution is: .
~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
Graphically, we have a parabola: .
The question is: when is the graph above the x-axis?
Since the parabola opens upward,
. . it is positive outside of its x-intercepts.
The x-intercepts are: .
And we can "see" the solution . . .
If the problem were: .Code:| ♥ | ♥ | | ♥ | ♥ | ♥ | ♥ - - * - - - + - * - - - -4 * | * 2 * | |
. . the solution is between the x-intercepts.
. . . . .