# Math Help - Factoring ax + c

1. ## Factoring ax + c

If you were to solve this 64y^2 - 9 would it be y=.375?

What would this look like factored?

2. ## Re: Factoring ax + c

Solve?

If you set it equal to zero, you have the difference of two squares equal to zero.

Can you think of something that, when squared, equals 64y^2 ?
Call that "a". Then "b" = 3.

a^2 - b^2 = (a + b)( a - b)

Setting this to zero and solving will give you two solutions.

3. ## Re: Factoring ax + c

You could also

$64y^2-9=0$

$\implies 64y^2=9$

$\implies 8y=\pm 3$

4. ## Re: Factoring ax + c

Originally Posted by britth
If you were to solve this 64y^2 - 9 would it be y=.375?

What would this look like factored?
Solve what - it needs to be equal to something (probably 0 since that does give your answer)

Use the difference of two squares as TheChaz suggested to factor it