If you were to solve this 64y^2 - 9 would it be y=.375?

What would this look like factored?

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- Dec 15th 2011, 08:01 PMbritthFactoring ax + c
If you were to solve this 64y^2 - 9 would it be y=.375?

What would this look like factored? - Dec 15th 2011, 08:31 PMTheChazRe: Factoring ax + c
Solve?

If you set it equal to zero, you have the difference of two squares equal to zero.

Can you think of something that, when squared, equals 64y^2 ?

Call that "a". Then "b" = 3.

a^2 - b^2 = (a + b)( a - b)

Setting this to zero and solving will give you two solutions. - Dec 16th 2011, 08:03 PMsbhatnagarRe: Factoring ax + c
You could also

$\displaystyle 64y^2-9=0$

$\displaystyle \implies 64y^2=9$

$\displaystyle \implies 8y=\pm 3$ - Dec 17th 2011, 02:42 AMe^(i*pi)Re: Factoring ax + c