Originally Posted by

**polskon** So my exam is in 2 days and I am having so much trouble. I am a new member, thanks for taking the time to view this question.

**If an object is thrown downward at 26 m/s from the top of a building, 102m high, the equation relating to displacement (meters) and time (seconds) is:**

**s = 1/2 gt^2 + 26t + 102**

**Find the time for an object to reach the ground from the top. Use g=-9.81**

So I have come up with: (I am new to this; sq = square root symbol, sorry)

**-26 +/- sq (26)^2 - 4(-4.905)(102) / -9.81**

My problem occurs when my two answers, rougly, equal:

s= -7.9247

and

s= -2.624

I am confused as to why I have 2 negative times. One should be positive and one negative, correct?

Thank you