you are geometrically diluting/mixing 0.1 g of powder A with 100g of powder B, how many times do you have to mix the 2 together to finish the process?
*each time you can only mix an equal portion of powder B to what you currently have mixed.
3. The attempt at a solution
So the first time you mix them it will be
0.1 g + 0.1 g --> 2^0
0.2 g + 0.2 g --> 2^1
0.4 g + 0.4 g -->2^2???
so with the formula is it? 101.1 = 0.1*2^n ???
I don't know what to do from here?
take 0.2 g of powder B and mix it with your 0.2 g -----> 0.4 g total
take 0.4 g of powder B and mix it with you 0.4 g -----> 0.8 g
continue untill you used up all of the 100 g of powder B, so I have to figure out how many "mixes" I did before getting to the final mass of 100 g powder B + 0.1 g powder A.
Well, most truthfully, I didn't get anything. Having established the reliable procedure, there was nothing left for me to do. It's your homework.
Let's see: and n = 8.97.
This suggests you may have missed somehting - perhaps that the original exponent was "n+1" rather than "n". Fix that.
In any case, that is not all. We must then answer the question.
"how many times do you have to mix the 2 together to finish the process?"
Ask yourself, "Can I REALLY mix things 0.97 times?" I'm thinking you need only whole numbers. What do you think?