3x^1/3 -16x^1/3 -35=0

I substituted x^1/3 for u and end up getting stuck at

3u^2 -16u-35 What do I do from here?

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- December 9th 2011, 12:01 PMdaword177Quadratic
3x^1/3 -16x^1/3 -35=0

I substituted x^1/3 for u and end up getting stuck at

3u^2 -16u-35 What do I do from here? - December 9th 2011, 12:05 PMPlatoRe: Quadratic
- December 9th 2011, 12:06 PMHallsofIvyRe: Quadratic
That's a quadratic equation (once you add the "= 0") so if you cannot factor, complete the square or use the quadratic formula.

- December 9th 2011, 12:08 PMearbothRe: Quadratic