Last question for now - Complete the factorization

**bashemgud** · December 7th 2011, 03:54 PM

Ok, so we have this on homework and never covered in clas and I dont even know where to begin

Says complete the factorization
-48x^5y^8 = -6x^3y^4 ( )

**skeeter** · December 7th 2011, 03:58 PM

Originally Posted by bashemgud

Ok, so we have this on homework and never covered in clas and I dont even know where to begin

Says complete the factorization
-48x^5y^8 = -6x^3y^4 ( )

$(unknown \, \, factor) = \frac{-48x^5y^8}{-6x^3y^4}$

**Prove It** · December 7th 2011, 04:01 PM

Originally Posted by bashemgud

Ok, so we have this on homework and never covered in clas and I dont even know where to begin

Says complete the factorization
-48x^5y^8 = -6x^3y^4 ( )

$\displaystyle \begin{align*} -48x^5y^8 &= -6x^3y^4 \\ 0 &= 48x^5y^8 - 6x^3y^4 \\ 0 &= 6x^3y^4\left(8x^2y^4 - 1\right) \\ 0 &= 6x^3y^4\left[\left(2\sqrt{2}\,x\,y^2\right)^2 - 1^2\right] \\ 0 &= 6x^3y^4\left(2\sqrt{2}\,x\,y^2 - 1\right)\left(2\sqrt{2}\,x\,y^2 + 1\right) \end{align*}$

Can you solve the equation now?

**bashemgud** · December 7th 2011, 04:01 PM

so I just divide it?

**bashemgud** · December 7th 2011, 04:02 PM

I think I am even more confused .

**Prove It** · December 7th 2011, 04:04 PM

Originally Posted by bashemgud

I think I am even more confused .

So am I. When asking a question, it helps to use some notation that can be understood, or give some explanation of what you wanted help doing...

**bashemgud** · December 7th 2011, 04:10 PM

Sorry, I am confused why the question has ( ) that are empty.

**skeeter** · December 7th 2011, 04:13 PM

Originally Posted by bashemgud

Sorry, I am confused why the question has ( ) that are empty.

( ... ) is the factor you're supposed to find if I interpret the problem correctly.

**Prove It** · December 7th 2011, 04:23 PM

Originally Posted by skeeter

( ... ) is the factor you're supposed to find if I interpret the problem correctly.

Assuming that is what it means (and it could really mean anything...)

$\displaystyle \begin{align*} -48x^5y^8 &= -6\cdot 8x^3x^2y^4y^4 \end{align*}$

What is left over when you take out $\displaystyle \begin{align*} -6x^3y^4 \end{align*}$ as a factor?

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