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- Dec 7th 2011, 03:04 PM #1

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## Value of h=48t-16t^2 when t = 2 and t = 2.5.

The two questions are similar but I keep getting way different answers

A water rocket is launched upwards with an initial velocity of 28 ft/sec. Its height H in feet after t seconds is given by h=48t-16t^2. Determine the height of the rocket after 2.5 secs after it has been launched.

The second question is the same, but 2.0 secs after launch

Thanks so much guys

- Dec 7th 2011, 03:18 PM #2

- Dec 7th 2011, 03:28 PM #3

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- Dec 7th 2011, 03:31 PM #4
## Re: Value of h=48t-16t^2 when t = 2 and t = 2.5.

This is because after 1.5 seconds, the rocket is descending.

- Dec 7th 2011, 03:31 PM #5

- Dec 7th 2011, 03:51 PM #6

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