Thread: ordered of pairs

In 1953, L.J.Mordell said that there were only four ordered triples of integers (x, y, z) for which x^3 +y^3 +z^3 = 3 .one of these is (1, 1, 1). What are the other three ordered triples?

(4, 4, -5)
(4, -5, 4)
(-5, 4, 4)

can you give me explanation

I saw your question.
I thought that I could answer it.
I assumed, since the claim was that there were exactly three more solutions, and since the equation is symmetric in x/y/z, that the solutions would be symmetric.
I assumed that two of the variables were equal.
I tried a few smaller numbers, and considered powers of small numbers.
I came across the given solution.
I typed in into the box, and hit "Post quick reply".

Good Explanation!

Originally Posted by HallsofIvy

Good Explanation!

It probably won't earn me the "Best MHF Helper 2011" award...

If anything, I'd like to see a little more confidence and effort in the world