In 1953, L.J.Mordell said that there were only four ordered triples of integers (x, y, z) for which x^3 +y^3 +z^3 = 3 .one of these is (1, 1, 1). What are the other three ordered triples?
I saw your question.
I thought that I could answer it.
I assumed, since the claim was that there were exactly three more solutions, and since the equation is symmetric in x/y/z, that the solutions would be symmetric.
I assumed that two of the variables were equal.
I tried a few smaller numbers, and considered powers of small numbers.
I came across the given solution.
I typed in into the box, and hit "Post quick reply".