In 1953, L.J.Mordell said that there were only four ordered triples of integers (x, y, z) for which x^3 +y^3 +z^3 = 3 .one of these is (1, 1, 1). What are the other three ordered triples?

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- December 7th 2011, 10:41 AMsri340ordered of pairs
In 1953, L.J.Mordell said that there were only four ordered triples of integers (x, y, z) for which x^3 +y^3 +z^3 = 3 .one of these is (1, 1, 1). What are the other three ordered triples?

- December 7th 2011, 11:03 AMTheChazRe: ordered of pairs
(4, 4, -5)

(4, -5, 4)

(-5, 4, 4) - December 7th 2011, 11:33 AMsri340Re: ordered of pairs
can you give me explanation

- December 7th 2011, 11:39 AMTheChazRe: ordered of pairs
I saw your question.

I thought that I could answer it.

I assumed, since the claim was that there were exactly three more solutions, and since the equation is symmetric in x/y/z, that the solutions would be symmetric.

I assumed that two of the variables were equal.

I tried a few smaller numbers, and considered powers of small numbers.

I came across the given solution.

I typed in into the box, and hit "Post quick reply". - December 7th 2011, 12:02 PMHallsofIvyRe: ordered of pairs
Good Explanation!

- December 7th 2011, 12:05 PMTheChazRe: ordered of pairs