I feel so stupid for having top ask for help again, but I have been trying to figure this out for several hours now

$\displaystyle 2x^{\frac{1}{3}}={\frac{81}{8}}^{-1}$

I multiplied both sides by two to eliminate the fraction

$\displaystyle 4x^{\frac{1}{3}}=27x^{-1}$

Then I multiplied both sides by $\displaystyle x^{\frac{1}{3}}$

Result

$\displaystyle 4=27^{\frac{-4}{3}}$

And I'm stuck.

Would you say I have any hope of getting into Advanced Mathematics, if I can't even solve a problem like this?

Thank you!