1. ## (-1(1-x)))^-2 algebra problem

I have
$\frac{1}{(x-1)^2}$

And to solve a binomial problem I need the x part in form (1 +/- x) - ie I need a positive 1.

I can get to:
$\frac{1}{(-1(1-x))^2}$

But how can I remove one bracket so I am left with one bracket? The squaring makes it positive so am a bit stuck.

Angus

2. ## Re: (-1(1-x)))^-2 algebra problem

You're right, and this is because $(x-1)^2=[-(x-1)]^2=(1-x)^2$.

$\frac{1}{(x-1)^2}$

$=(x-1)^{-2}$

$=(-1+x)^{-2}$

$=(-1)^{-2}(1-x)^{-2}$

$=(1-x)^{-2}$

3. ## Re: (-1(1-x)))^-2 algebra problem

Originally Posted by angypangy
(-1(1 - x)))^-2
Should be:
[-1(1 - x)]^(-2)