(-1(1-x)))^-2 algebra problem

**angypangy** · December 2nd 2011, 04:51 AM

I have
$\frac{1}{(x-1)^2}$

And to solve a binomial problem I need the x part in form (1 +/- x) - ie I need a positive 1.

I can get to:
$\frac{1}{(-1(1-x))^2}$

But how can I remove one bracket so I am left with one bracket? The squaring makes it positive so am a bit stuck.

Angus

**Quacky** · December 2nd 2011, 04:58 AM

You're right, and this is because $(x-1)^2=[-(x-1)]^2=(1-x)^2$ .

$\frac{1}{(x-1)^2}$

$=(x-1)^{-2}$

$=(-1+x)^{-2}$

$=(-1)^{-2}(1-x)^{-2}$

$=(1-x)^{-2}$

**Wilmer** · December 2nd 2011, 08:53 AM

Originally Posted by angypangy

(-1(1 - x)))^-2

Should be:
[-1(1 - x)]^(-2)

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