Thread: Averages.

For the life of me I'm unable to locate a way to calculate this issue.. I'm trying to take the average of 3 numbers, however each number has more or less weight on the total average than the other 2 numbers.. For example.

(Number 1) 50% total weight
(Number 2) 37.5% total weight
(Number 3) 12.5% total weight
All equaling 1 total average. Any help would be appreciated. Thank you!

Hello, cmpprice!

I'm trying to take the average of 3 numbers. .However each number
has more or less weight on the total average than the other 2 numbers.

For example:

Number 1: 50% total weight
Number 2: 37.5% total weight
Number 3: 12.5% total weight

All equaling one total average.

Look at it this way:

. .

Their weights are in the ratio .

Their average is: .

I am fix , cannot get this.

Originally Posted by cmpprice

For the life of me I'm unable to locate a way to calculate this issue.. I'm trying to take the average of 3 numbers, however each number has more or less weight on the total average than the other 2 numbers.. For example.

(Number 1) 50% total weight
(Number 2) 37.5% total weight
(Number 3) 12.5% total weight
All equaling 1 total average. Any help would be appreciated. Thank you!

Hello.

There are 3 different people, one with 50% weight, 37.5% weight, and 12.5% weight. For this example, the 50% weight person is X, 37.5 weight person is W, and 12.5% person is U. So we have 50%, X. 37.5% ,W. 12.5% U.

Now we know that 50% = 50/100 = 1/2 = 4/8
37.5% = 3/8
12.5% = 1/8, You can divide 3/8 by 3.

Now lets refer back to X, W, and U. For simple purposes, lets give them values. X = 100, W = 150, and U = 200.

Now to find the average... [ (4/8)100 + (3/8)150 + (1/8)200 ]/3 = y
You divide everything by 3, because you're trying to find the average of all three people.
Or you can use, [ (4/8)X + (3/8)W + (1/2)U ]/3 = Y

Or, simply 0.50X+ 0.375Y+ 0.125Z.