Re: An easy question? Averages.

Hello, cmpprice!

Quote:

I'm trying to take the average of 3 numbers. .However each number

has more or less weight on the total average than the other 2 numbers.

For example:

Number 1: 50% total weight

Number 2: 37.5% total weight

Number 3: 12.5% total weight

All equaling one total average.

Look at it this way:

. . $\displaystyle \begin{array}{cccccc}\text{Number} & \text{Weight} \\ X & 50\% &=& \frac{4}{8} \\ \\[-3mm] Y & 37.5\% &=& \frac{3}{8} \\ \\[-3mm] Z & 12.5\% &=& \frac{1}{8} \end{array}$

Their weights are in the ratio .$\displaystyle X:Y:Z \:=\:4:3:1$

Their average is: .$\displaystyle \dfrac{4X + 3Y + Z}{8}$

Re: An easy question? Averages.

I am fix , cannot get this.