# Thread: 3x + y = 4(2-z)

2. ## Re: 3x + y = 4(2-z)

Originally Posted by ingyaningya
$x = \frac{4(2-z) -y}{3}$

$y = 4(2-z)-3x$

$z = 2-\frac{3x+y}{4}$

What do you exactly need solve?

For "x"

4. ## Re: 3x + y = 4(2-z)

Originally Posted by ingyaningya

3x + y = 4(2-z)...Solve for x.

Subtract y from both sides. By doing so, you will isolate the term 3x.

3x = 4(2 - z) - y

We now divide both sides by the coefficient of x, which is the number 3.

x = [4(2 - z) - y]/3

By the way, you can use the distributive rule in terms of 4(2 - z) to simplify further if needed.