I have a problem factorizing that equation 2x^3-5x^2-6x+8 until now I've found the root x=2 and x=-4/3 and I'm stuck there Thanks for the help
Follow Math Help Forum on Facebook and Google+
Originally Posted by sebastien I have a problem factorizing that equation 2x^3-5x^2-6x+8 until now I've found the root x=2 and x=-4/3 and I'm stuck there Thanks for the help It doesn't factorise... And what you have listed are not roots.
made a mistake my equation is 3x^3-5x^2-6x+8 and not the other one
Originally Posted by sebastien made a mistake my equation is 3x^3-5x^2-6x+8 and not the other one Well, like you have found, x = 2 is a root, which means (x - 2) is a factor. Long dividing gives and factorising the resulting quadratic gives