$\displaystyle \frac{1}{n}-\frac{-1^n}{n^2}<0.000001$

can i solve this algebraically?

if not, how do i solve it?

many thanks.

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- Nov 28th 2011, 12:17 PM #1

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- Nov 28th 2011, 01:45 PM #2

- Nov 29th 2011, 10:23 AM #3

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- Nov 29th 2011, 10:29 AM #4
## Re: Log problem.

for even, $\displaystyle k>499999$ So $\displaystyle \frac{n}{2}>499999$ remembering that $\displaystyle n=2k$

for odd, $\displaystyle k>500000$ So $\displaystyle \frac{n-1}{2}>500000$ remembering that $\displaystyle n=2k+1$

What is the solution which satisfies for all $\displaystyle n$?