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Can some one please let me know how the value for x is 2.13?

Thanks a lot.

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- Nov 28th 2011, 06:49 AMthashrifNeed to find value for X
http://www.coolmetron.co.uk/maths.gif

Can some one please let me know how the value for x is 2.13?

Thanks a lot. - Nov 28th 2011, 07:04 AMSironRe: Need to find value for X
What have you tried? Have you learned to solve equations yet?

- Nov 28th 2011, 09:23 AMthashrifRe: Need to find value for X
- Nov 28th 2011, 08:21 PMmathlandRe: Need to find value for X
- Nov 29th 2011, 04:38 AMthashrifRe: Need to find value for X
- Nov 29th 2011, 12:04 PMHallsofIvyRe: Need to find value for X
So the problem is to solve $\displaystyle 1.6911= 1.6242\frac{\frac{1+ x^2}{12}}{1.0062}$.

First do the arithmetic on the right:$\displaystyle \frac{1.6242}{12(1.0062)}= 0.134516$ to 6 decimal places. That means the equation is $\displaystyle 1.611= 0.134516(1+ x^2)$. Divide both sides by 0.134516: $\displaystyle 0.134516= x^2+ 1$.

Subtract 1 from both sides. $\displaystyle x^2= -0.8655$ which has no**real**number soltutions. if you are allowed complex numbers, the solution is plus or minus $\displaystyle \sqrt{0.8655}$ times i. - Nov 29th 2011, 01:49 PMmathlandRe: Need to find value for X
**I worked this problem twice and did not come close to your answer for x.**

You say that x = 2.13.

If x = 2.13, then after evaluation, we should get the same answer on both sides of the equation.

Let x = 2.13

1.6199 = 1.6242 [(1 + x^2)/12)] divided by 1.0062

1.6199 = 1.6242 [(1 + (2.13)^2)/12)] divided by 1.0062

1.6199 = 1.6242 [(1 + 4.5369)/12)] divided by 1.0062

1.6199 = 1.6242 [(5.5369)/12)] divided by 1.0062

As I continued to simplify, I did not get 1.6199 on both sides of the equation. So, the answer for x that you suggested (2.13) is not correct.

Find a calculator and continue simplifying where I ended my computation. I'm sure you will agree. - Nov 29th 2011, 07:17 PMbjhopperRe: Need to find value for X
- Nov 30th 2011, 01:00 PMBabyMiloRe: Need to find value for X
Mistake?

First it should be 1.6911 instead of 1.611.

Secondly,

$\displaystyle \frac{1.611}{0.134516}= 11.98 (2 d.p.)$

Correct me if I am wrong.

http://www.wolframalpha.com/input/?i=1.6199+%3D+1.6242*%28%281+%2B+x^2%29%2F%2812*1. 0062%29%29+find+x