You have to solve following system of equations :
184 is divided into two parts such that one-third of one part may exceed one-seventh of the other part by 8, then the greater part is _______.
The possible answers are 72, 110, 112, 114.
I have tried this question in several ways, but I am unable to solve this question. Can someone point me in the right direction.
I'll continue where princeps ended his reply.
x + y = 184..........Equation A
(x/3) = (y/7) + 8...Equation B
I will solve Equation A for either x or y. How about for y?
x + y = 184
y = 184 - x
I will now plug that for y in Equation B to find the value of x.
(x/3) = [(184 - x)/7)] + 8
Multiply by 21 to clear the fractions on both sides of the equation.
After doing so, we get
7x = 3(184 - x) + 8(21)
7x = 552 - 3x + 168
7x = -3x + 720
7x + 3x = 720
10x = 720
x = 720/10
x = 72
Let x = 72 in either Equation A or B above.
I will use Equation A.
x + y = 184
72 + y = 184
y = 184 - 72
y = 112
Which is the answer? Can you tell me given the amount of work that was done?