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Math Help - How to solve for x ?

  1. #1
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    How to solve for x ?

    It's not quadratic equation.
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by totalnewbie
    It's not quadratic equation.
    <br />
x^{1/2}+x-2=0<br />

    Substitute y=\sqrt{x}, then the equation becomes:

    <br />
y^2+y-2=0<br />

    then solve for y, and examine all the possible solution to
    determine which are sensible.

    Note: As y^2+y-2 factorises to (y-1)(y+2)
    so does x^{1/2}+x-2 to (x^{1/2}-1)(x^{1/2}+2).

    RonL
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