It's not quadratic equation.
$\displaystyleOriginally Posted by totalnewbie
x^{1/2}+x-2=0
$
Substitute $\displaystyle y=\sqrt{x}$, then the equation becomes:
$\displaystyle
y^2+y-2=0
$
then solve for $\displaystyle y$, and examine all the possible solution to
determine which are sensible.
Note: As $\displaystyle y^2+y-2$ factorises to $\displaystyle (y-1)(y+2)$
so does $\displaystyle x^{1/2}+x-2$ to $\displaystyle (x^{1/2}-1)(x^{1/2}+2)$.
RonL