# Math Help - How to solve for x ?

1. ## How to solve for x ?

It's not quadratic equation.

2. Originally Posted by totalnewbie
It's not quadratic equation.
$
x^{1/2}+x-2=0
$

Substitute $y=\sqrt{x}$, then the equation becomes:

$
y^2+y-2=0
$

then solve for $y$, and examine all the possible solution to
determine which are sensible.

Note: As $y^2+y-2$ factorises to $(y-1)(y+2)$
so does $x^{1/2}+x-2$ to $(x^{1/2}-1)(x^{1/2}+2)$.

RonL