It's not quadratic equation.

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- Feb 19th 2006, 01:42 AMtotalnewbieHow to solve for x ?
It's not quadratic equation.

- Feb 19th 2006, 02:25 AMCaptainBlackQuote:

Originally Posted by**totalnewbie**

x^{1/2}+x-2=0

$

Substitute $\displaystyle y=\sqrt{x}$, then the equation becomes:

$\displaystyle

y^2+y-2=0

$

then solve for $\displaystyle y$, and examine all the possible solution to

determine which are sensible.

Note: As $\displaystyle y^2+y-2$ factorises to $\displaystyle (y-1)(y+2)$

so does $\displaystyle x^{1/2}+x-2$ to $\displaystyle (x^{1/2}-1)(x^{1/2}+2)$.

RonL