hi - I've got an intergral to solve but when seperating this fraction get a different answer to my Maple solution. Take a look and show me where i'm going wrong because i'm stumped!

$\displaystyle \frac{x+2}{1-4x^2}$

i) $\displaystyle =\frac{x+2}{(1-2x)(1+2x)}$

ii) $\displaystyle =\frac{5}{4(1-2x)} + \frac{3}{4(1+2x)}$

but my program tells me its $\displaystyle =\frac{-5}{4(1-2x)} + \frac{3}{4(1+2x)}$

I can't see why the negative sign is introduced. Any ideas??

Cheers, F