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Math Help - LN

  1. #1
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    LN

    2^{1-x}=3
    LN2^{1-x}=LN3
    I am stuck. I have to use LN but it doesn't seem to work.
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  2. #2
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    Re: LN

    \ln a^b = b\ln a does this help?
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  3. #3
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    Re: LN

    After that I have no idea what to do.
    1-x(LN2)=LN3

    -x(LN2)=LN3-1

    x=LN3-1/-LN2
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  4. #4
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    Re: LN

    \ln2^{1-x}=\ln3

    Becomes

    (1-x)\ln2=\ln3

    1-x=\frac{\ln3}{\ln2}
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