Given:
Show that:
Obvi, factor the second equation and we get
So, we only have to show that ab=cd.
Can anyone crack it?
Say, in what domain are we solving this? If it's the reals, than this assumption doesn't hold. Take for example the way less general (a=1, b=1):
So your assumption would imply that c+d=2, but one can find other c and d that solve the above system. Let u=c+d, so from the second:
Adding twice to the first equation
As, expected, one solution is u=c+d=1+1=2. But the other roots
are the roots of the quadratic:
And those are .
So, c+d can be equal to those numbers, and not just to 2=1+1=a+b.
For example:
Where
one of the roots of the above quadratic.