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Math Help - solve for x please

  1. #1
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    solve for x please

    find x:
    15.196=2*sqrt(3^2+x^2) + 10-x
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  2. #2
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    Re: solve for x please

    Take 10-x from both sides, then square both sides. Does that make sense?
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  3. #3
    MHF Contributor Amer's Avatar
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    Re: solve for x please

    15.196 = 2\sqrt{3^2+x^2} + 10 -x

    x -10 + 15.196 = 2 \sqrt{3^2+x^2} square both sides

    (x + 5.196)^2 = \left( 2\sqrt{3^2+x^2}\right)^2
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  4. #4
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    Re: solve for x please

    Quote Originally Posted by Amer View Post
    15.196 = 2\sqrt{3^2+x^2} + 10 -x

    x -10 + 15.196 = 2 \sqrt{3^2+x^2} square both sides

    (x + 5.196)^2 = \left( 2\sqrt{3^2+x^2}\right)^2
    so do i do this?
    (x+5.196)(x+5.196)=18+2x^2
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  5. #5
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    Re: solve for x please

    Yes, expand the LHS then group like terms.
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  6. #6
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    Re: solve for x please

    is the right hand side proper?
    cas i tried (2*sqrt(3^2+3^2))^2 and got 72
    and 18+2(3)^2 is 36.
    so is this the correct RHS: 2(18+2x^2)
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  7. #7
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    Re: solve for x please

    Try (x+5.196)(x+5.196)=2(18+2x^2)
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