you can take a factor
as you can see you can factor b-dv in all
now factor (b-dv)(r+1)
it is nice and clear
I have the following that I want to solve for v.
S = b - dv + r(b - dv) + c[b - dv + r(b - dv)] + t(b - dv + r(b - dv) + c[b - dv + r(b - dv)])
I started by getting rid of the parentheses:
S = b - dv + rb - rdv + cb - cdv + crb - crdv + tb - tdv + trb - trdv + tcb - tcdv + tcrb - tcrdv
Then, I reordered the terms and combined some like so:
S = b(1 + r + c + cr + t + tr + tc + tcr) - dv(1 - r - c - cr - t - tr - tc - tcr)
I have a few more steps that I took, but am wondering if someone could show me a better way to simplify and solve.
What I have so for is this, but I think I made a mistake along the way:
v = S - b[1 + r + c(1 + r + t + tr) + t + tr] / -d[1 - r - c(1 - r - t - tr) - t - tr]
Any guidance is appreciated.
Thanks,
Erik