Results 1 to 4 of 4

- November 15th 2011, 10:07 AM #1

- Joined
- Oct 2008
- From
- Maine
- Posts
- 70

## Skydiving

given formula is t=v/2g

V is final velocity, g is gravitational constant of 32 ft/sec2 and t is the time of the fall. Skydiver jumps at 6000 feet. How long did it take to reach final velocity of -96 feet per second.

If I use the info they give me I get 1.5 seconds but I did a little research on the formula because i was curious if I needed to do anything with the 6000 ft and found that the 2 shouldn't be in the formula at all? Is this correct? I'm not sure if this is the right forum.

- November 15th 2011, 10:18 AM #2

- November 15th 2011, 11:04 AM #3

- Joined
- Oct 2008
- From
- Maine
- Posts
- 70

- November 15th 2011, 11:49 AM #4