# Skydiving

• Nov 15th 2011, 09:07 AM
Jman115
Skydiving
given formula is t=v/2g

V is final velocity, g is gravitational constant of 32 ft/sec2 and t is the time of the fall. Skydiver jumps at 6000 feet. How long did it take to reach final velocity of -96 feet per second.

If I use the info they give me I get 1.5 seconds but I did a little research on the formula because i was curious if I needed to do anything with the 6000 ft and found that the 2 shouldn't be in the formula at all? Is this correct? I'm not sure if this is the right forum.
• Nov 15th 2011, 09:18 AM
e^(i*pi)
Re: Skydiving
Quote:

Originally Posted by Jman115
given formula is t=v/2g

V is final velocity, g is gravitational constant of 32 ft/sec2 and t is the time of the fall. Skydiver jumps at 6000 feet. How long did it take to reach final velocity of -96 feet per second.

If I use the info they give me I get 1.5 seconds but I did a little research on the formula because i was curious if I needed to do anything with the 6000 ft and found that the 2 shouldn't be in the formula at all? Is this correct? I'm not sure if this is the right forum.

It's not needed here but it may be needed for another part of the question
• Nov 15th 2011, 10:04 AM
Jman115
Re: Skydiving
I was actually asking whether or not the 2 should actually be part of that formula. the one connected to the g. During my research on the formula I found someone who claimed it was not supposed to be there.
• Nov 15th 2011, 10:49 AM
skeeter
Re: Skydiving
Quote:

Originally Posted by Jman115
given formula is t=v/2g

V is final velocity, g is gravitational constant of 32 ft/sec2 and t is the time of the fall. Skydiver jumps at 6000 feet. How long did it take to reach final velocity of -96 feet per second.

If I use the info they give me I get 1.5 seconds but I did a little research on the formula because i was curious if I needed to do anything with the 6000 ft and found that the 2 shouldn't be in the formula at all? Is this correct? I'm not sure if this is the right forum.

$\displaystyle v_f = v_0 - gt$
for $\displaystyle v_0 = 0$ , $\displaystyle t = -\frac{v_f}{g}$