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Thread: which has the least value...

  1. #1
    Senior Member
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    which has the least value...

    ok im a little lost on this problem...

    if n is less than and equal to -2, which of the following has the least value?

    a. -$\displaystyle \frac{1}{n^{2}}$

    b. $\displaystyle \frac{1}{n^{2}}$

    c.$\displaystyle \frac{1}{n}$

    d.$\displaystyle \frac{1}{n-1}$

    e.$\displaystyle \frac{1}{n+1}$

    to do this problem i plugged in values, so i chose n= -5 and selected a as my answer...but of course this is wrong, i would like to know why.


    thanks in advance.
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  2. #2
    Super Member Quacky's Avatar
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    Re: which has the least value...

    Ok, your method is valid. Let's say $\displaystyle n=-5$

    a)$\displaystyle -\frac{1}{(-5)^2}$

    $\displaystyle =\frac{-1}{25}$

    b)$\displaystyle \frac{1}{(-5)^2}$

    $\displaystyle =\frac{1}{25}$

    c)$\displaystyle \frac{1}{n}$

    $\displaystyle =\frac{-1}{5}$

    d)$\displaystyle \frac{1}{n-1}$

    $\displaystyle =\frac{-1}{6}$

    e)$\displaystyle \frac{1}{n+1}$

    $\displaystyle =\frac{-1}{4}$

    EDIT: Nevermind! Which of these values is the most negative?
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  3. #3
    Super Member Quacky's Avatar
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    Re: which has the least value...

    Corrected an error.
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  4. #4
    Senior Member
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    Re: which has the least value...

    thanks, it appears i read it wrong....
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