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Math Help - which has the least value...

  1. #1
    Senior Member
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    which has the least value...

    ok im a little lost on this problem...

    if n is less than and equal to -2, which of the following has the least value?

    a. - \frac{1}{n^{2}}

    b. \frac{1}{n^{2}}

    c. \frac{1}{n}

    d. \frac{1}{n-1}

    e. \frac{1}{n+1}

    to do this problem i plugged in values, so i chose n= -5 and selected a as my answer...but of course this is wrong, i would like to know why.


    thanks in advance.
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  2. #2
    Super Member Quacky's Avatar
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    Windsor, South-East England
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    Re: which has the least value...

    Ok, your method is valid. Let's say n=-5

    a) -\frac{1}{(-5)^2}

    =\frac{-1}{25}

    b) \frac{1}{(-5)^2}

    =\frac{1}{25}

    c) \frac{1}{n}

    =\frac{-1}{5}

    d) \frac{1}{n-1}

    =\frac{-1}{6}

    e) \frac{1}{n+1}

    =\frac{-1}{4}

    EDIT: Nevermind! Which of these values is the most negative?
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  3. #3
    Super Member Quacky's Avatar
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    Re: which has the least value...

    Corrected an error.
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  4. #4
    Senior Member
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    Re: which has the least value...

    thanks, it appears i read it wrong....
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