# Thread: which has the least value...

1. ## which has the least value...

ok im a little lost on this problem...

if n is less than and equal to -2, which of the following has the least value?

a. -$\displaystyle \frac{1}{n^{2}}$

b. $\displaystyle \frac{1}{n^{2}}$

c.$\displaystyle \frac{1}{n}$

d.$\displaystyle \frac{1}{n-1}$

e.$\displaystyle \frac{1}{n+1}$

to do this problem i plugged in values, so i chose n= -5 and selected a as my answer...but of course this is wrong, i would like to know why.

2. ## Re: which has the least value...

Ok, your method is valid. Let's say $\displaystyle n=-5$

a)$\displaystyle -\frac{1}{(-5)^2}$

$\displaystyle =\frac{-1}{25}$

b)$\displaystyle \frac{1}{(-5)^2}$

$\displaystyle =\frac{1}{25}$

c)$\displaystyle \frac{1}{n}$

$\displaystyle =\frac{-1}{5}$

d)$\displaystyle \frac{1}{n-1}$

$\displaystyle =\frac{-1}{6}$

e)$\displaystyle \frac{1}{n+1}$

$\displaystyle =\frac{-1}{4}$

EDIT: Nevermind! Which of these values is the most negative?

3. ## Re: which has the least value...

Corrected an error.

4. ## Re: which has the least value...

thanks, it appears i read it wrong....