# Thread: which has the least value...

1. ## which has the least value...

ok im a little lost on this problem...

if n is less than and equal to -2, which of the following has the least value?

a. - $\frac{1}{n^{2}}$

b. $\frac{1}{n^{2}}$

c. $\frac{1}{n}$

d. $\frac{1}{n-1}$

e. $\frac{1}{n+1}$

to do this problem i plugged in values, so i chose n= -5 and selected a as my answer...but of course this is wrong, i would like to know why.

2. ## Re: which has the least value...

Ok, your method is valid. Let's say $n=-5$

a) $-\frac{1}{(-5)^2}$

$=\frac{-1}{25}$

b) $\frac{1}{(-5)^2}$

$=\frac{1}{25}$

c) $\frac{1}{n}$

$=\frac{-1}{5}$

d) $\frac{1}{n-1}$

$=\frac{-1}{6}$

e) $\frac{1}{n+1}$

$=\frac{-1}{4}$

EDIT: Nevermind! Which of these values is the most negative?

3. ## Re: which has the least value...

Corrected an error.

4. ## Re: which has the least value...

thanks, it appears i read it wrong....