Your conclusions are good, but your addition needs some work.
The 'k' in the second tableau should be "k + 2g"
Hello, I have tried this problem out but get stuck on one part.
Find an equation involving g, h and k that makes this augmented matrix consistent.
1 -4 7 g
0 3 -5 h
-2 5 -9 k
so i try and put this in trangular form by multiplying row_1 by 2 and adding it to row_3 and end up with
1 -4 7 g
0 3 -5 h
0 -3 5 k
can i assume since row 2 and row 3 are almost the same, just scaled by -1 that i can take out one of the equations since they are the same? would column 3 be a free variable?
Hello, carlo_b!
Find an equation involving g, h and k that makes this augmented matrix consistent.
. .
Your next step is a bit off . . .
One more step . . .Can i assume since row 2 and row 3 are almost the same, just scaled by -1,
that i can take out one of the equations since they are the same? . . Yes
Would column 3 be a free variable? . Yes
If is not equal to , the system is inconsistent.
To be consistent: .
Ahh, too slow again . . .