1. ## Simplify Equation

Okay, I've been working on these problems for hours now and it has been killing me. I'm on the edge of. . . let me get to the point. . . Here's the problem.

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Here's what I gotten:

$27u^9/z^14$
PLEASE ASSIST. I've tried.. Tried so much.. Wasted so many sheets of paper, this is ridiculous.

2. ## Re: Simplify Equation

Take it one step at a time.

Starting with:

$(\frac{x^{-1}u^3}{3z^{-3}})$

$x^{-1}=\frac{1}{x}$ and $z^{-3}=\frac{1}{z^3}$

This means we can rewrite this as:

$\frac{z^3u^3}{3x}$

Cubing this:

$[\frac{z^3u^3}{3x}]^3$

$\frac{(z^3u^3)^3}{(3x)^3}$

Take it one step at a time, starting with $(z^3)^3$

$=(z^3)(z^3)(z^3)$

= $z^9$ using the rule that $n^a\cdot{n^b}=n^{a+b}$

We can generalize this to have: $(n^a)^b=n^{a\times{b}}$

So do this to each term, remembering to cube the $3$.

Once you get there, it just becomes a case of cancelling.

It looks like you're nearly finished with your simplifying. So no worries.