I dont have any idea how to start this equation.

How can i simplify this equation??

(sorry my english)

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- November 13th 2011, 08:25 AMFabio010Solving equations
I dont have any idea how to start this equation.

How can i simplify this equation??

(sorry my english) - November 13th 2011, 08:35 AMe^(i*pi)Re: Solving equations
- November 13th 2011, 08:38 AMFabio010Re: Solving equations
never mind.

I dont know why but in my head ln(a) + ln (b) = ln (ab) if a = b...

sorry. - November 13th 2011, 08:41 AMHallsofIvyRe: Solving equations
What you do need to think about is that logarithm is a "one to one" function. That is, ln(a)= ln(b) if and only if a= b.

- November 13th 2011, 08:44 AMe^(i*pi)Re: Solving equations
- November 13th 2011, 08:58 AMFabio010Re: Solving equations
So:

? - November 13th 2011, 09:02 AMe^(i*pi)Re: Solving equations
- November 13th 2011, 09:14 AMFabio010Re: Solving equations
Ok thanks for the help !

- November 13th 2011, 09:59 AMe^(i*pi)Re: Solving equations