First case:

Second case:

So we get from case 2, and from case 1. Put them together to give the whole range of solutions and you get that

Results 1 to 4 of 4

- November 12th 2011, 10:05 AM #1

- Joined
- Nov 2011
- Posts
- 30

## |x-1| = 1 - x

Hey forum, I'm dealing with this one

I use the definition of the absolute value of an arbitrary argument which gives

We see that it is true for the second condition, because

Therefore, the answer must be that x must be smaller than 1. But the equation is also true for**x=1**! What's up with that?

- November 12th 2011, 10:12 AM #2

- November 12th 2011, 10:17 AM #3

- Joined
- Nov 2011
- Posts
- 30

- November 12th 2011, 11:04 AM #4

- Joined
- Apr 2005
- Posts
- 17,290
- Thanks
- 2146