So we get from case 2, and from case 1. Put them together to give the whole range of solutions and you get that
Hey forum, I'm dealing with this one
I use the definition of the absolute value of an arbitrary argument which gives
We see that it is true for the second condition, because
Therefore, the answer must be that x must be smaller than 1. But the equation is also true for x=1 ! What's up with that?