First case:

Second case:

So we get from case 2, and from case 1. Put them together to give the whole range of solutions and you get that

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- November 12th 2011, 11:05 AM #1

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## |x-1| = 1 - x

Hey forum, I'm dealing with this one

I use the definition of the absolute value of an arbitrary argument which gives

We see that it is true for the second condition, because

Therefore, the answer must be that x must be smaller than 1. But the equation is also true for**x=1**! What's up with that?

- November 12th 2011, 11:12 AM #2

- November 12th 2011, 11:17 AM #3

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- November 12th 2011, 12:04 PM #4

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