I don't understand the method. It may be correct and valid, I just don't understand it.
I agree with
Together they worked problems.
So:
We have two equations:
I'd substitute the first into the second, to get:
Hi!
J'onn J'onnz worked 7 more problems than Clark Kent. Together they worked 55 problems. How many did each boy work?
I got 31 for J'onn and 24 for Clark:
J'onn = J
Clark = C
J = 7 + C
7 + C = 55
C = 48
48/2 = 24 ==> Clark
24 + 7 = 31 ==> J'onn
Another way is: 55 + 7 = 62
62/2 = 31
31 - 7 = 24
I think my methods are flawed and that's the reason for my seeking help.
One more point to what Quacky said:
You were asked the question "how many problems did each boy work?"
By that question being asked, you know there are two unknowns to find.
For x unknowns, you need x equations to solve for them.
Thus, for two unknowns, you need to establish two equations based on the given information to find them.
Once you have the same number of equations as unknowns, you can then start to solve the problem. Quacky suggested substituting one equation into the other one and that's definitely your best bet.
No, J+ C= 55 so (7+ C)+ C= 7+ 2C= 55
No, 2C= 48 so C= 48/2= 24C = 48
Okay, now you have the correct value- but you had said before "Clark = C" by which I assume you meant that C was the number of problems Clark worked. Having said that, it makes no sense to say "7+ C= 55" or to divide C by 2 to get the number of problems Clark worked.48/2 = 24 ==> Clark
Why? What part of the statement of this problem leads you to add 7 to 62?24 + 7 = 31 ==> J'onn
Another way is: 55 + 7 = 62
You do come to the correct answer but what logic led you to it?62/2 = 31
31 - 7 = 24
I think my methods are flawed and that's the reason for my seeking help.
It is true that if J= 7+ C so C= J- 7. Then J+ C= J+ J- 7= 2J- 7= 55. Now you have that 2J= 55+ 7= 62 and then J= 31. If that was your reasoning, great- but say so!