Could someone explain in more details this simplification?

Thanks

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- Nov 11th 2011, 08:07 AMcxz7410123simplification
Could someone explain in more details this simplification?

Thanks - Nov 11th 2011, 08:12 AMe^(i*pi)Re: simplification
- Nov 11th 2011, 08:28 AMveileenRe: simplification
I hope you know the formula: (*).

For the first fraction, the numerator is , using (*) it becomes: . (I used the rule )

For the second fraction, the numerator is , which can also be written: (I used the rule ). Using (*) again, we obtain .

So we have:

(I rearranged the factors, I hope this helped).

Now, if we want we can apply (*) again for :

(I used the rule ).