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Math Help - Relatively basic fraction multplication!

  1. #1
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    Relatively basic fraction multplication!

    Hi all,

    The below expression is part of a longer equation which I have simplified for this example. I would like to remove the r from the very bottom denominator. What do I multiply the remaining variables by?

    a/b * (1-cd)/(1-(cd/r)) + e/f

    Many thanks in advance!
    Last edited by ktharmer; November 11th 2011 at 12:19 AM. Reason: equation didn't display
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  2. #2
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    Re: Relatively basic fraction multplication!

    \frac{a}{b} \cdot \frac{1-cd}{1-\frac{cd}{r}} + \frac{e}{f}

    i assume that by "very bottom denominator" you mean the \frac{cd}{r} part.


    multiply everything by 1/r

     \frac{a}{b} \cdot \frac{1-cd}{r \left(1-\frac{cd}{r} \right)} + \frac{e}{fr}

     = \frac{a}{b} \cdot \frac{1-cd}{r-cd} + \frac{e}{fr}
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  3. #3
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    Re: Relatively basic fraction multplication!

    Thanks!
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  4. #4
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    Re: Relatively basic fraction multplication!

    oh dear, how silly of me, if you wanted a fraction that was equivalent to he first one, that wont be it....as the above is multiplied by (1/r)

    hopefully you made appropriate adjustments to ther est of your equation.
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  5. #5
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    Re: Relatively basic fraction multplication!

    Quote Originally Posted by ktharmer View Post
    a/b * (1-cd)/(1-(cd/r)) + e/f
    1 - cd/r = (r - cd) / r
    So:
    a/b * [r(1 - cd) / (r - cd)] + e/f
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