Thread: Transformations of a parabola.

So here is the question.

y = (3 -x)(x +1) is an inverted parabola. Coordinates are (-1,0) and (3,0) for the x-intercepts, and the y intercept is (0,3). Axis of symmetry is (1,0).

The parabola is moved 2 units to the left and 7 units down. Give the equation for the parabola in its new position and give the coordinates of the y-intercept.

If you can answer this, explain it with as simple terms as possible, please.

Originally Posted by squelia

So here is the question.

y = (3 -x)(x +1) is an inverted parabola. Coordinates are (-1,0) and (3,0) for the x-intercepts, and the y intercept is (0,3). Axis of symmetry is (1,0).

The parabola is moved 2 units to the left and 7 units down. Give the equation for the parabola in its new position and give the coordinates of the y-intercept.

If you can answer this, explain it with as simple terms as possible, please.

complete the square to get the quadratic in vertex form, ...





translate 2 units left, 7 units down ...





evaluate at to find the y-intercept

btw ... wrong forum.