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Math Help - Transformations of a parabola.

  1. #1
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    Post Transformations of a parabola.

    So here is the question.

    y = (3 -x)(x +1) is an inverted parabola. Coordinates are (-1,0) and (3,0) for the x-intercepts, and the y intercept is (0,3). Axis of symmetry is (1,0).

    The parabola is moved 2 units to the left and 7 units down. Give the equation for the parabola in its new position and give the coordinates of the y-intercept.

    If you can answer this, explain it with as simple terms as possible, please.
    Last edited by mr fantastic; November 11th 2011 at 12:49 AM. Reason: Re-titled.
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  2. #2
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    Re: Parabola Help Please??

    Quote Originally Posted by squelia View Post
    So here is the question.

    y = (3 -x)(x +1) is an inverted parabola. Coordinates are (-1,0) and (3,0) for the x-intercepts, and the y intercept is (0,3). Axis of symmetry is (1,0).

    The parabola is moved 2 units to the left and 7 units down. Give the equation for the parabola in its new position and give the coordinates of the y-intercept.

    If you can answer this, explain it with as simple terms as possible, please.
    y = -x^2 + 2x + 3

    y = -(x^2 - 2x) + 3

    complete the square to get the quadratic in vertex form, y = a(x-h)^2 + k ...

    y = -(x^2 - 2x + 1) + 3 + 1

    y = -(x -1)^2 + 4

    translate 2 units left, 7 units down ...

    y = -[(x-1) + 2]^2 + 4 - 7

    y = -(x + 1)^2 - 3

    evaluate at x = 0 to find the y-intercept

    btw ... wrong forum.
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