Hi - I hoped someone maybe able to help me understand this question:

$\displaystyle absolutevalue\(\frac{(x+1)}{(x-3)(x-5)}) < \frac{1}{2}$

(apologies but I can't find the syntax for absolute value sign)

I know that I would need to square both sides in order to remove the modulus. But when rearranging I dont end up with a product so unsure how to proceed.

Thanks, F