if z1,z2,z3...zn lie on circle mod(z)=2 then the value of mod(z1+z2+...+zn)-4*mod(1/z1+1/z2+1/z3...+1/zn) is

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- Nov 9th 2011, 08:09 AMprasumcomplex no
if z1,z2,z3...zn lie on circle mod(z)=2 then the value of mod(z1+z2+...+zn)-4*mod(1/z1+1/z2+1/z3...+1/zn) is

- Nov 9th 2011, 08:26 AMAmerRe: complex no
is the question

or

- Nov 9th 2011, 09:16 AMprasumRe: complex no
- Nov 9th 2011, 10:02 AMPlatoRe: complex no
- Nov 9th 2011, 10:19 AMAmerRe: complex no
- Nov 9th 2011, 10:26 AMveileenRe: complex no
Let .

* That inequalities aren't really useful, if you multiply by -4 the second one it becomes (so you can't add them).