Hey,

I came upon a problem where I cannot understand why has no real solutions for the polynomial equation . Any help is greatly appreciated.

Sam

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- Nov 8th 2011, 10:26 AMArcherSamNo Real Solutions
Hey,

I came upon a problem where I cannot understand why has no real solutions for the polynomial equation . Any help is greatly appreciated.

Sam - Nov 8th 2011, 10:37 AMSironRe: No Real Solutions
You're talking about the equation, but what's ? Is ?

- Nov 8th 2011, 10:47 AMArcherSamRe: No Real Solutions
Yes, :

- Nov 8th 2011, 10:51 AMe^(i*pi)Re: No Real Solutions
- Nov 8th 2011, 10:53 AMArcherSamRe: No Real Solutions
- Nov 8th 2011, 10:54 AMDevenoRe: No Real Solutions
suppose that:

which real numbers have negative squares?

- Nov 8th 2011, 10:56 AMArcherSamRe: No Real Solutions
LOL, the non-negative property of even exponents has conquered me again. Thanks Deveno.

- Nov 8th 2011, 10:59 AMBobBaliRe: No Real Solutions
When findin the zeros for.

*Not possible to have square root of a negative number, hence

no real roots. Also if you graph the parabola for the above

Quad equation, you will see it is a transaltion of 6units vertically

up the yaxis, and the graph doesn't cut the xaxis; hence no solutions. - Nov 8th 2011, 11:03 AMBobBaliRe: No Real Solutions
When findin the zeros for.

*Not possible to have square root of a negative number, hence

no real roots. Also if you graph the parabola for the above

Quad equation, you will see it is a transaltion of 6units vertically

up the yaxis, and the graph doesn't cut the xaxis; hence no solutions.