Problem: A baseball player travels from his home city, Jasonville, to Giambi City for a baseball game. He drives at m miles an hour. After the game, he flies home instead, traveling at p miles an hour. If the distance from jasonville to Giambi City is v miles, and it took him j hours longer to drive than to fly, what is j?
The answer is vm-vp. I set up a rate distance time chart for the first leg there and the second leg home. Then I made x+j=v/m (rate formula) and x=v/p Then I subsituted v/p for x and set j = to v/m-v/p. That was the answer I got. What did I do wrongly?