Domain and Range

Hi,

I'm just wondering if I'm correct and also what notation I should use here.

The question is asking for the domain and range of $f(x,y)=e^{y-x^2}$

I think the domain is $Domain \subset R^2$ and $Range>0$

Thanks for your help.

Re: Domain and Range

yes, the domain is a subset of $\mathbb{R}^2$ . but in this case, if f(x,y) makes sense for all real numbers x and y,

then the domain equals $\mathbb{R}^2$ .

now $e^x$ is always positive, so we know the range is a subset of the positive reals. the question is, can $y-x^2$

turn out to be any real number? and it can: let's say we have a certain real number r in mind. then we could pick x = 0, and y = r.

so now we ask, given that $y-x^2$ can be any real number, can $e^{y-x^2}$ be any positive real number?

suppose s is positive. then ln(s) makes sense, so we can pick (x,y) = (0,ln(s)), and then $e^{\ln(s)-0} = e^{\ln(s)} = s$ .

so we see any positive real number is in the range of f, and only positive real numbers are in the range of f.

so range(f) = $\{x \in \mathbb{R}: x > 0\}$ . this is sometimes also written: $\mathbb{R}^+$ or as the interval $(0,\infty)$

Re: Domain and Range

Not sure what your answer is for the Domain: it's all of $\mathbb{R}^2$ .

Your Range is correct.

(Deveno beat me by less than 1 minute.)