Given that log p=0.6, log q=0.2, find the value of N if N=-2pq^2 Thanks
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Originally Posted by brian890 Given that log p=0.6, log q=0.2, find the value of N if N=-2pq^2 change each log to an exponential, then substitute for p and q
I forgot to mention that it said you can't use a calculator. It would be p=10^0.6 and q=10^0.2 How would I calculate that? EDIT: Nevermind, I think I got it, thanks N=-2(10^0.6)(10^0.2)^2 =-2(10^0.6)(10^0.4) =-2(10) =-20 Is this correct?
you don't need a calculator to find N ... mind your rules for exponents.
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