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Math Help - Help with Logarithms?

  1. #1
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    Help with Logarithms?

    Given that log p=0.6, log q=0.2, find the value of N if N=-2pq^2

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  2. #2
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    Re: Help with Logarithms?

    Quote Originally Posted by brian890 View Post
    Given that log p=0.6, log q=0.2, find the value of N if N=-2pq^2
    change each log to an exponential, then substitute for p and q
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  3. #3
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    Re: Help with Logarithms?

    I forgot to mention that it said you can't use a calculator.

    It would be p=10^0.6 and q=10^0.2
    How would I calculate that?

    EDIT: Nevermind, I think I got it, thanks
    N=-2(10^0.6)(10^0.2)^2
    =-2(10^0.6)(10^0.4)
    =-2(10)
    =-20
    Is this correct?
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  4. #4
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    Re: Help with Logarithms?

    N = -2 \cdot 10^{0.6} \cdot (10^{0.2})^2

    you don't need a calculator to find N ... mind your rules for exponents.
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