# Thread: Help with Logarithms?

1. ## Help with Logarithms?

Given that log p=0.6, log q=0.2, find the value of N if N=-2pq^2

Thanks

2. ## Re: Help with Logarithms?

Originally Posted by brian890
Given that log p=0.6, log q=0.2, find the value of N if N=-2pq^2
change each log to an exponential, then substitute for p and q

3. ## Re: Help with Logarithms?

I forgot to mention that it said you can't use a calculator.

It would be p=10^0.6 and q=10^0.2
How would I calculate that?

EDIT: Nevermind, I think I got it, thanks
N=-2(10^0.6)(10^0.2)^2
=-2(10^0.6)(10^0.4)
=-2(10)
=-20
Is this correct?

4. ## Re: Help with Logarithms?

$N = -2 \cdot 10^{0.6} \cdot (10^{0.2})^2$

you don't need a calculator to find N ... mind your rules for exponents.